#include <stdio.h>

double power(double n, int p); // ANSI函数原型

int main(void)
{
    printf("\n");

    double x, xpow;

    int exp;

    printf("Enter a number and the positive integer power");

    printf(" to which\nthe number will be raised. Enter q");

    printf(" to quit.\n");

    while (scanf("%lf%d", &x, &exp) == 2)
    {
        xpow = power(x, exp); // 函数调用
        printf("%.3g to the power %d is %.5g\n", x, exp, xpow);
        printf("Enter next pair of numbers or q to quit.\n");
    }

    printf("Hope you enjoyed this power trip -- bye!\n");

    return 0;
}

double power(double n, int p) // 函数定义
{
    double pow = 1;
    int i;
    for (i = 1; i <= p; i++)
    {
        pow *= n;
    }
    return pow; // 返回pow的值
}
